← Algebraic methods
Roots and coefficients — building an equation from its roots
A recurring reverse-direction task: given the roots (or a passing point), find the original quadratic or cubic's constants.The two directions, and which method fits
- FROM ROOTS TO EQUATION: if r₁ and r₂ are roots of a quadratic, the quadratic is a(x − r₁)(x − r₂) = 0 — expand and match to ax² + bx + c to find a, b, c.
- FROM A CUBIC'S ROOTS: the same idea extends — a cubic with roots r₁, r₂, r₃ is a(x − r₁)(x − r₂)(x − r₃) = 0, expanded and matched term by term.
- FROM GIVEN POINTS: substitute each (x, y) pair into the general form to get one equation per point, then solve the resulting equations simultaneously for the unknown constants.
- SUM AND PRODUCT OF ROOTS: for ax² + bx + c = 0, the sum of roots = −b/a and the product of roots = c/a — useful for finding an expression like a² + b² without solving for the roots individually.
Forgetting the leading coefficient when building from roots
Writing a quadratic as just (x − r₁)(x − r₂) = 0 only works when the leading coefficient is 1. If the question gives a leading coefficient other than 1 (like the "3" in 3x³ + ax² + bx + c), it must be multiplied through AFTER expanding the root factors, or every constant found will be wrong by that factor.| What you are given | Method to use |
|---|---|
| Two roots of a quadratic | a(x − r₁)(x − r₂) = 0, expand and match |
| Three roots of a cubic | a(x − r₁)(x − r₂)(x − r₃) = 0, expand in stages |
| Two points the curve passes through | Substitute each point into the general form, solve simultaneously |
| An expression like a² + b² using roots a, b | Use sum of roots = −b/a and product = c/a, then (a+b)² − 2ab |
Practice for this standard covers the whole topic — flashcards and quiz.