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AS 91523 · 2023 paper · diffraction glasses

Question 3(d) Merit

Practises Diffraction & refraction

At a fair, children buy “Rainbow Glasses” made of diffraction gratings in a cardboard frame. Steve shines a laser pointer of wavelength 643 nm (6.43 × 10⁻⁷ m) through one of the gratings onto a wall. The pattern is a bright red spot at the centre, with slightly dimmer red spots either side. The wall is 1.43 m from the grating, and the distance from the central bright spot to the second dimmer spot is 1.75 m.

λ643 nm (6.43 × 10⁻⁷ m)
grating to wall1.43 m
centre to 2nd spot1.75 m

Looking at a spot of white light through the glasses, the children see the white spot with spectra on either side (“rainbows”). Give an in-depth explanation: describe where the spectra occur, explain the position of the colours in them and why they are there, and include a labelled sketch.

The 2023 paper, page 7 ↗ Marking schedule, page 6 ↗

Work it out

Try it on paper first. Stuck? Take one hint at a time.

  1. 1 Where is the light white, and why?

    Straight through, at the centre: at θ = 0 every colour has zero path difference, so they are all bright together and mix into white.
  2. 2 For the first order, what path difference does each colour need?

    One of its own wavelengths: violet the least (about 400 nm), red the most (about 700 nm).
  3. 3 So at what angle is each colour bright?

    sin θ = nλ / d: the shorter the wavelength, the smaller the angle. Violet is bright closest to the centre, red furthest out, and the other colours in between.
  4. 4 Where do the spectra appear, and what goes in the sketch?

    On both sides of the white centre, one complete spectrum for each order (n = 1, 2), each with violet on the inside and red on the outside. Sketch the white central spot labelled n = 0, then on each side the n = 1 and n = 2 spectra, each running violet to red outwards. With these glasses (d = 1.66 × 10⁻⁶ m) the first-order spectrum runs from about 14° (violet) to 25° (red).
Answer A white spot at the centre (n = 0), where every colour has zero path difference, then a complete spectrum on each side for each order. In each spectrum violet is nearest the centre and red furthest out: each colour is bright where the path difference is a whole number of its own wavelengths (d sin θ = nλ), and violet’s short wavelength gets there at a smaller angle than red’s long one.

What the marker wanted

  • Achieved One idea: a complete spectrum is seen, violet inside and red outside; a whole-wavelength path difference puts the waves in phase; a whole-wavelength path difference gives a maximum; or waves in phase give a maximum.
  • Merit The right reasoning for violet inside and red outside: red’s longer wavelength needs a larger path difference, so a larger angle in nλ = d sin θ.

In our words, from NZQA’s 2023 marking schedule.

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Common mistake

Putting red on the inside. NZQA’s 2023 report lists spectra drawn the wrong way round among answers that did not reach Achieved. It is the reverse of a prism: with a grating, the shortest wavelength is nearest the centre.

How did it go?

Got it moves it further out. Review brings it back tomorrow.