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AS 91524 · 2025 paper · rotational motion

Question 2(b) Merit

Practises Rotational dynamics

Rīhari and Jane are on a playground roundabout of radius 1.30 m. Rīhari stands on it while Jane pushes; from rest she steadily accelerates it so it takes 12.0 s to make 4.00 rotations.

r1.30 m
4.00 rotations in 12.0 s
I (roundabout + Rīhari)430 kg m²

Rīhari then drags his foot along the ground, bringing the roundabout to a stop over 19.2 s.

Calculate the average torque that slows it, if the roundabout and Rīhari have a rotational inertia of 430 kg m².

The 2025 paper, page 5 ↗ Marking schedule, page 3 ↗

Work it out

Try it on paper first. Stuck? Take one hint at a time.

  1. 1 How quickly does the roundabout lose its angular velocity?

    From 4.1888 rad s⁻¹ to 0 in 19.2 s: α = (ω − ω0) / t = (0 − 4.1888) / 19.2 = −0.218 17 rad s⁻².
  2. 2 Which equation turns an angular acceleration into a torque?

    τ = Iα = 430 × (−0.218 17) = −93.81 N m.
  3. 3 What does the minus sign tell you?

    That the torque acts against the rotation. It is what slows the roundabout down.
Answer 93.8 N m, acting against the rotation (−93.8 N m).

What the marker wanted

  • Achieved One of: the angular acceleration (−0.218 rad s⁻²), or τ = Iα used correctly on a wrong angular acceleration.
  • Merit The right torque.

In our words, from NZQA’s 2025 marking schedule.

How did it go?

Got it moves it further out. Review brings it back tomorrow.