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AS 91526 · 2024 paper · DC and capacitors
Question 1(a) Achieved
Practises DC circuits
Stefan investigates new and used car batteries. His car has a new battery with an EMF of 12.0 V and an internal resistance of 0.0500 Ω, connected to a 7.00 Ω load.
| ε | 12.0 V |
|---|---|
| r | 0.0500 Ω |
| R | 7.00 Ω |
Explain the meaning of the term EMF.
Work it out
Try it on paper first. Stuck? Take one hint at a time.
-
1 Where does the energy that pushes charge round a circuit come from?
From the battery. As charge passes through it, stored chemical energy is turned into electrical energy. -
2 How does “energy per charge” become a number of volts?
One volt is one joule per coulomb. The EMF is the energy the battery gives each coulomb of charge that passes through it, so 12.0 V means 12.0 J per coulomb. -
3 How could you measure it with a voltmeter?
Draw no current. With nothing flowing, no voltage is lost across the internal resistance, so the voltmeter across the terminals reads the EMF itself.
What the marker wanted
- Achieved A correct meaning: the energy given to each coulomb of charge, or the voltage across the terminals when no current is drawn.
In our words, from NZQA’s 2024 marking schedule.
✕Common mistake
Answering about the voltage a changing magnetic field sets up in a coil. This EMF belongs to a battery. NZQA’s 2024 report says many candidates could only discuss EMF as part of electromagnetic induction.How did it go?
Got it moves it further out. Review brings it back tomorrow.